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b 73.9 g of methanol from –35°C to 59°C Heat = cal C 3.90 kg of lead from –33°C to 731°C Heat = cal d 67.4 g of ice from –77°
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0 Specific heat of methanol = 0.506 Cal/200k For 73.9 g of methanol from - 35e to se ... Heat = mxsx (t2-to m amass. s=specif@ Specific heat of lead = 0.0305 Al/ok. For, 3.9 kg of lead from - 33°C to 731°C. Heal= mxsx (t2-t) m = 3.9 kg kg = 3.9 X 100

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