Question

No.: Date: I As a fuel, H₂ (al produces only non-polluting H₂ Orgy when it burns moreover, it combines with O₂ cgl in a fuel cell to provide eletrical energy it calculate AH, 45°, and 46 per moll Of H2197 07 298k.. 1). 1s the spontaneity of this reaction dependent on T] ni). At what' temperature does the reaction become spontaneous mon.

Hi,can you help me answer a and b.thank you so much for your help.

Answer 1

w The balanced equation of Harg combines with 0216) i Hyrgy + '02 (5) --> H2O(g) 4H" - H products - EW'Seactants - Hipanen – [Hibce) + Yo Honey] Standard Hillary = -241.82 ks lmol His ao OH - -241.82 – (0+0] = -241.82 kt Imor as - [ ŚChelo - (5 2463 +1280x693)] By standard value of

S Hera) = 1887 illa moll Šib.com = 131 J Ill.md S0345) = 205 Jik-mol .: AS - 188.7 - [131+ 15 (205] = 188.7-(233.5) = - 44.8 3111-mol DQ = oHº-pasº AH = -241-82 kJ/mol AC = -44.8 Jllcmol = -44.8 1000 kJ/I-mol =-0.044.8 Kit hemol T = 298 OG = = AQ = -241.82-(298) (-0.0448) -241.82 + 13.35 -228.5 kJ ( for spontaneove reaction så = -ve - spontaneity of a reaction depends on Temperature By increasing temperature , AG becomes positive, then it is non-Spontaneove. So spontaneity depends on temperature SA 2416

il when oh zo it is in equilibrium يد - - اي = م At equilibrium - 0 = -241.82 - 7 (-0.0448) 241.82 = 0.00448 (Ⓡ) - f = 241.82 R 0.00448 = 5397 K temperature the reaction is Spontaneous Below 5397k sh=-ve because (b) 20315) ► 30209) AHO = -285.4 € / mos os - 137.55 I l kmol = 0.138 Kolk.mol = 25 c = 25+213 = 298 sa = -265.4– (29876437532 (0.138) - -285.4- 41.12 = - 326.52 KB > Di i8 negative, so the above reaction is Spontaneous

(ii Songs + O2(g) 250gg) → SK > Shº-tasº AM = _Gelat, o$ =-187.933 = -0.188 KJ]x.no) T=25C= 25+243 = 298 K si at asc = -98 - (298) (-48747 (-0.1887 = -98 + 56 = -41.96 KB 250 is -41.98 , so it is spontaneous DG at 98 % -4.6 KB oli at 2988 = -41.9811 It observe that wao increases with temperature increasing → at 7= 90 c = 900 +213 = 113k så , SH- taso - -98- (1173) 60.188) = -96 + 220.5 = +122-52 K3 bi= tue, so it is non-spontaneous reaction (Note: OS SU Sozcu) = -187.9 J , Not –187.9 Kb )