A solution containing 1.25 g of KI is combined with a solution containing 2.42 g of Pb(NO3)2. What mass of PbI2 would result using the following equation?
2KI(aq) + Pb(NO3)2(aq) = 2 KNO3(aq) + PbI2(s).
A solution containing 1.25 g of KI is combined with a solution containing 2.42 g of...
Consider the balanced equation of KI reacting with Pb(NO3)2 to form a precipitate. 2KI(aq)+Pb(NO3)2(aq)⟶PbI2(s)+2KNO3(aq) What mass of PbI2 can be formed by adding 0.413 L of a 0.140 M solution of KI to a solution of excess Pb(NO3)2?
What are the identities of the precipitate in each of the following reactions: A) AgNO3 (aq) + KI (aq) ------> Ag (s) + KNO3 (aq) B) Pb(NO3)2 (aq) + 2KI (aq) ------> PbI2 (s) + 2KNO3 (aq) C) Na3PO4 (aq) + 3Ca(NO3)2 (aq) ------> Ca3(PO4)2 (s) + 6NaNO3 (g) D) MgSO4 (aq) + BaCl2 (aq) ------> BaSO4 (s) + MgCl2 (aq) E) COCl2 (aq) + Ca(OH)2 (aq) ------> CaCl2 (aq) + Co(OH)2 (s)
Question 4 Status: Not yet answered Points possible: 1.00 Consider the balanced equation of KI reacting with Pb(NO3), to form a precipitate. 2 KI (aq) + Pb(NO3)2 (aq) + Pbl (8) + 2 KNO3(aq) What mass of Pbl, can be formed by adding 0.489 L of a 0.364 M solution of KI to a solution of excess Pb(NO3)2? Answer: Question 5 Status: Not yet answered Points possible: 1.00 Suppose that you decompose 24.45 g of Ni 03, which has a...
1. A 75.0-mL sample of 0.200 M Lead(II) nitrate, Pb(NO3)2, is reacted with 75.0 mL of 0.450 M KI solution and the following precipitation reaction occurs. Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq) (a) Determine the limiting reactant. (b) How many grams of PbI2 will be formed if the yield is 100%? (c) What is the percent yield if 6.45 g of PbI2 were obtained? (2) K2Cr2O7(aq) + FeCl2(aq) → CrCl3(aq) + Fe(NO3)3(aq) (a) Determine the net ionic reactions and...
An aqueous solution containing 8.16 g of lead(II) nitrate is added to an aqueous solution containing 6.57 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO3)2(aq) + 2 KCl(aq) + PbCl,(s) + 2 KNO3(aq) What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 91.6%. How many grams of precipitate is recovered? precipitate recovered: How many grams of the...
Homework 6. Chapter 8 Be sure to show your work if you want to the problem.) set up and cancelling units, dimensional analys up and cancelling units, dimensional analysis is half Numbers 1-4 all refer to the following equatic CH, +5 0, --> 30, + 4 HẠO How many moles of water will be produced when 8. moles of propane, CH, are burned? 2. How many grams of oxygen are needed to produce 3 moles of carbon dioxide? 3. When...
2KI (aq) + Pb(NO3)2 (aq) + PbI, (s) + 2KNO3 (aq). How much 0.7 M KI solution in liters will completely precipitate the Pb2+ in 2.1 L of 0.18 M Pb(NO3), solution? Do not include units in your answer and round to two significant figures. Druiden bela
Determine whether each of the following equations for precipitation reactions is correct. If not, write the correct equation. If no reaction occurs, choose NO REACTION. Ba(NO3)2(aq)+(NH4)2SO4(aq)→BaSO4(s)+2NH4NO3(aq)Ba(NO3)2(aq)+(NH4)2SO4(aq)→BaSO4(s)+2NH4NO3(aq) correct incorrect no reaction BaS(aq)+2KCl(aq)→BaCl2(s)+K2S(aq)BaS(aq)+2KCl(aq)→BaCl2(s)+K2S(aq) correct incorrect no reaction 2KI(aq)+Pb(NO3)2(aq)→PbI2(s)+2KNO3(aq)2KI(aq)+Pb(NO3)2(aq)→PbI2(s)+2KNO3(aq) correct incorrect no reaction Pb(NO3)2(aq)+2LiCl(aq)→2LiNO3(s)+PbCl2(aq)Pb(NO3)2(aq)+2LiCl(aq)→2LiNO3(s)+PbCl2(aq) correct incorrect no reaction
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) ΔH = -3352 kJ How much heat is released when 8.07 g of Al react with O2(g) at 25 oC and 1 atm? Select the oxidation-reduction reaction(s)? 1. Cl2(g) + ZnBr2(aq) → ZnCl2(aq) + Br2(l) 2. Pb(ClO4)2(aq) + 2 KI(aq) → PbI2(s) + 2 KClO4(aq) 3. CaCO3(s) → CO2(g) + CaO(s) Select the strong acid in aqueous solution from the set below. Group...
When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright yellow solid precipitate forms Calculate the mass of the solid produced (molar mass = 461 g/mol) when starting with a solution containing 242.36 g of potassium iodide (molar mass = 166 g/mol), assuming that the reaction goes to completion. Give your answer to three significant figures 2KI (aq) Pb(NO3)2 (aq) » Pbl2 (s) 2KNO3 () g