For the reaction g) + 2Y(g) = 22(g) K = 3.46 10-2 at a temperature of...
22 A) For the reaction 2A(g)+3B(g)⇌C(g) Kc = 40.0 at a temperature of 165 ∘C∘ Calculate the value of Kp 22 B) For the reaction X(g)+2Y(g)⇌2Z(g) Kp= 1.87×10−2 at a temperature of 67 ∘C Calculate the value of Kc Part A For the reaction 2A(g) + 3B(g) = C(g) Kc = 40.0 at a temperature of 165 °C. Calculate the value of Kp. Express your answer numerically. View Available Hint(s) | ΑΣφ ? Submit Part B For the reaction X(g)...
For the reaction X(g)+2Y(g)⇌3Z(g) Kp = 3.18×10−2 at a temperature of 109 ∘C . Calculate the value of Kc. Express your answer numerically.
For the reaction 3A(g)+2B(g)⇌C(g) Kc = 73.0 at a temperature of 379 ∘C . Calculate the value of Kp. Express your answer numerically. For the reaction X(g)+2Y(g)⇌3Z(g) Kp = 2.82×10−2 at a temperature of 195 ∘C . Calculate the value of Kc. Express your answer numerically.
For the reaction X(g) + 3Y(g) = 32(g) K = 3.15x10-2 at a temperature of 255 °C Calculate the value of K.. Express your answer numerically. View Available Hint(s) IVO AL O ?
Please Answer Both Parts. Part A For the reaction 3A(g)+3B(g)⇌C(g) Kc = 44.0 at a temperature of 93 ∘C . Calculate the value of Kp. Express your answer numerically. Part B For the reaction X(g)+3Y(g)⇌3Z(g) Kp = 3.20×10−2 at a temperature of 351 ∘C . Calculate the value of Kc. Express your answer numerically.
Part A For the reaction 3A(g)+3B(g)⇌C(g) Kc = 35.0 at a temperature of 347 ∘C . Calculate the value of Kp. Express your answer numerically. Kp = SubmitHintsMy AnswersGive UpReview Part Part B For the reaction X(g)+3Y(g)⇌3Z(g) Kp = 2.30×10−2 at a temperature of 271 ∘C . Calculate the value of Kc. Express your answer numerically. Kc = SubmitHintsMy AnswersGive UpReview Part
Part A For the reaction 3A(g) + 3B(g) = C(g) Kc = 40.8 at a temperature of 163 °C. Calculate the value of K, Express your answer numerically. View Available Hint(s) IVO AJO o o o ?
Part A For the reaction The equilibrium constant, Kc is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp. is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation K = K (RT)An where R=0.08206 L-atın/K mol). T is the absolute temperature, and An is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N (g)...
For the reaction 2CH4(g)⇌C2H2(g)+3H2(g) 2 C H 4 ( g ) ⇌ C 2 H 2 ( g ) + 3 H 2 ( g ) K c = 0.135 at 1615 ∘C . What is Kp for the reaction at this temperature? Express your answer numerically. For the reaction N2(g)+3H2(g)⇌2NH3(g)N2(g)+3H2(g)⇌2NH3(g) KpKp = 5.15×10−3 at 333 ∘C . What is Kc for the reaction at this temperature? Enter your answer numerically.
For the reaction 2A(g)+3B(g)⇌C(g) Kc = 49.0 at a temperature of 249 ∘C Calculate the value of Kp Express your answer numerically. .