Using the ICE table
[A] | [B] | [C] | |
Initial | 0.550 | 1.10 | 0.650 |
Change | -x | -2x | +x |
Final | 0.550-x | 1.10-2x | 0.650+x |
0.550 - x = 0.350, x = 0.200
[B] = 1.10 - 2(0.200) = 0.700
[A] = 0.350, [C] = 0.850
Hence the value of Kc will be equal to 4.96
Note - Post any doubts/queries in comments section.
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