Question

Crystallography 23. The spacing between layers of molybdenum atoms is d=157 pm (picometers). Calculate the sin e, the angle o at which lambda 1 =154 pm. X-rays produce a maximum reflection for n = 1. Use the Reference table 3 for e. 00 30° 45° 60° 90° sin e 0 WISSN- NISMS cose tane undef. Incident plane wave 2d sin 6 0.01 d sin 8 Constructive interference when na = 2d sin Bragg's Law

Answer 1

2 d sindan for maximum reflection nel 2d sind - here d=157pm d=154pm sind = 154 2x 157 sino = 0.49 sine ~ 0.50 Sind = 9 = 30° $0=29.37"} from calculator