Question

NA = 6.0221367E23 Ka(CH3COOH) = 1.8x10E5 Kb(NH3) = 1.8x10E5 Ka(HCN) = 4.9x10E1 What is the pH...

NA = 6.0221367E23

Ka(CH3COOH) = 1.8x10E5

Kb(NH3) = 1.8x10E5

Ka(HCN) = 4.9x10E1

What is the pH of a 0.10 M CH3COOH(aq) solution?

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Answer #1

Answer- pH is 2.87PAGE NE DATE Chycoo- 0.1 м Сн соон Kq = 1.8 x 105 ; pH = ? CH₃COOH + How) 2 Hot + I OIM0 C -2 + x +2 0.1-x x x 0.1-x Ka = [4₂

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NA = 6.0221367E23 Ka(CH3COOH) = 1.8x10E5 Kb(NH3) = 1.8x10E5 Ka(HCN) = 4.9x10E1 What is the pH...
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