Question

Experiment 4 CHM 111 Datasheet Metal Results in Order of increasing Frequency (lowest one on top): Color of Flame Wavelength Range Frequency Range Cacla Orange 585-6oorm NaCl Ormas 585-620nm CuCl₂ green 490-570rm! IUCLI videt you- 420rm Bach yellow 570-5850 m Licl red 620-780nm SrCl2 Red | 620-780 nm TR6 CL vrolet 400-4200m I cscl vrolet You-4201 m) Unknown code: Unknown code:ft-115 Color of flame of unknown. vide 1. if unknown: CsCI, Kc) Roc! ID if unknown:__

need to find the frequency range

Answer 1

We know that the,

Frequency = Speed of light /Wavelength

using above equation we put the value of each wavelength range value to find each frequency range value.We show the calculation of the first two data set given and rest we do by same calculation .

Ans:- = Speed of light Wavelength - ve for (585- 620) nm = v= 3x108 ms-t (with 585 nm) 585x1.-4 m (0.0051–0-0048 )x1017 frequency range) =) V: 0.0051 X1017 Hz = v= 3x108 (with 620nm) 620X10-9 =) V: 0.0048x1017 Hz For (440-570)um = v= 3x108 ( with 440mm) (0.0068- 0.0052 )x1017 olunt (frequency range) . 440X10-9 v= 0.0068 X 1017 Hz = v= 3x108 570X10-9 ~= 0.0052 81017 Hz (with 570 nm) Similarly frequency lange ve C0.0075 -0.0071 ) x1017 HZ For H00- 420 mm va co.0052 - 0.0051) x 1017 Hz Fos (570-585)mm For (620 - 780) am For (620-780)um For (400-420) nm for (400-420) nm . voco.0048 -0.0038 ) x 1017 Hz v= (0.0048-0-00 38 ) x 107 Hz v= (0.0075 -0.0071 ) x 1017 Hz v= 0.0075 0.0071) × 1017 Hz Ics Scanned with CamScanner