Question

9,10,11,12. Not sure I am doing this right. Looking for some assistance. Thank you so much. playing catch up due to all the changes.

Tria Aspirin Brand (and amount of acetylsalicylic acid on label) Bayer 2) Average molar concentration of NaOH Solution B (from Part A) Trial 1* T Trial 2 T 3) Mass of aspirin tablet To. 4039 0.4049 4) Mass of pulverized aspirin sample 10. 370g 0,400 5) Initial buret reading 6.03ML 0.56m2 6) Final buret reading 116.88mL 117.44mL) 7) Volume of NaOH Solution B added 116.85mU16,88 ml 8) Moles of NaOH 16.02696 m2.0270lmol 9) Moles of acetylsalicylic acid in sample 26 , a6 xlound 270141634 10) Mass of acetylsalicylic acid in sample 14.8519 14.8660 11) Amount of acetylsalicylic acid per tablet (12) Mean amount of acetylsalicylic acid per tablet 13) Standard deviation for acetylsalicylic acid per tablet 14) RSD for acetylsalicylic acid per tablet 15) Relative percent error (%) ow all calculations related to Trial 1, standard deviation, RSD, and relative % error.

Answer 1

Trial-1:-

(9) Moles of acetylsalicylic acid in sample = Moles of NaOH used for titrating a complete sample.

Moles of acetylsalicylic acid in sample = 0.02701 mole

(10) Mass of acetylsalicylic acid in a sample = moles * molar mass

Mass of acetylsalicylic acid = (0.02701 mol )*(180.158 g/mol)

Mass of acetylsalicylic acid = 4.866 g

(11) Amount of acetylsalicylic acid per tablet = 0.403 g

Trial-2:-

(9) Moles of acetylsalicylic acid in sample = Moles of NaOH used for titrating a complete sample.

Moles of acetylsalicylic acid in sample = 0.02696 mole

(10) Mass of acetylsalicylic acid in a sample = moles * molar mass

Mass of acetylsalicylic acid = (0.02696 mol )*(180.158 g/mol)

Mass of acetylsalicylic acid = 4.866 g

(11) Amount of acetylsalicylic acid per tablet = 0.404 g

(12) Mean amount of acetylsalicylic acid per tablet = (trial-1 + trial-2)/2

Mean amount = (0.403 g + 0.404 g)/2

Mean amount= 0.4035 g