Question

Ph Phe Ph Ru(PPh34H2 (1.0 mol%) NaBH4 (1 eq.) H2O (2 eq.) Toluene, 100 °C, 22 h 100% (94%) Meo Meo 100% (78%) Ph. o 11 100% (92%) OAC 12 100% 13 85% Ph = Ph PhPh 10 100% (82%) Scheme 3. Reduction of other alkenes.

Q1 / What is the meaning of the ratios placed under the products, and why in some reactions are two numbers and some are one number, please explain the reason?

Q2 / Is the amount of reducing agent affected the result in this reaction?

Answer 1

Answer-

Ru(Ph3P)4,H2 is Wilkinson's Catalyst. It is extremely effective for homogeneous hydrogenation of non conjugated alkene and alkynes at ordinary temperature and pressure.Functional group like carbonyl , cyano nitro are not reduced under these conditions.

NaBH4 , H2O heating is a reducing reagent for Alkene and Alkynes. Please find attached file for Ans of Q1.

reaning of ratios placed under the product is there are two different reducing reagents are there. Wilkinson's catalyst. RuCPPh ada tz C 10 mols) NaBHq Cl eq), to czeg) Toulene a Both are the reducing agents and reducing products of compounds are given by both the reagent (1) is u (2) is prodrect by NaBly. Please find below the prodees ph Ru (PPh ₂), H2 com l a phe - 100% product. a reducing products of diffenet I both the reagent (1) is wilkinson cat produt below the product with % p" . 5 NOBH4, led H₂o.2ed toulene 100°C, 22h: Ph. - 94%. product formation. Rucppha) longly TT - 100), NaB44, leg. H20 20g 78% Habla reduced 78% of 4 to 6a phy Rucpphady, H2 linoly. will give 100%. 11. This reagent will not reduce to group. to PIN NaBH4Cred) 2.40 (2.ed) Rucp Phg) 4 H₂ ~ to - 929. 11 produeet feomation NaBH also will not reduce Amide AGO DAC A - The double bond in 8 is trans bond only reduce cis bond easily so not reduced and Ha, W.cat 8 to 12 Aco OAC Nabha (lea Hocaed) Aco! OAC - 100%. 12 Naprla reduced sto12 100% field. RuPphz), H2. Both the double bonds are more hindered. and & bond is trans also will not reduced by Hilkinson's catalyst. NagH 4 Clea) #20 c2eq). "OH 18 NaBly reduced 9 to 13 - 85%. 13 85%. If we increase NOBH4 mole more there is possibility of reduction of Another bond also. ph - 100% Hocatalyst reduced loor. RuCPPh ₂ )4, the Ph -ph 5 NaB44 (leg ho (209) phph 82% - Na 82% - NOBH 4 reduced to 82%.

Ans of Q.2

Yes , The amount of reducing agent (moles/ quantity) is definitely affect the result of reaction .

If we have two different double bond in reaction and used exact 1 mole of reducing agent will reduce more reactive bond only .And we use excess quantity and harsh condition it will reduce both the bond or percent product.

Hope you have cleared the concept.