Question

Assume an organic compound has a partition coefficient between water and ether equal to 8.48. If there are initially 7.52 grams of the compound dissolved in 70.0 mL of water, how many grams will remain in the aqueous layer after extraction with two 25.0 mL portions of ether?

Mass: ________ g

Answer 1

( partition Loefficient (k) = Molarity in molarity in Organic phase Aqueous phase → 8.48 = Molarity Molarity in in Ether phase Aqueous phase → - — Inital mass of organic Compound= 7.52g. Molar massor osganic compound M. 3/mol. 25 ml of each layer of two layer of ether. Tм (0) Laki 2 let's → layer of Ether & 2 extraction say, x gram of organic compound extracted in 1st Extraction 8.48 = x g 25 ml ather XM 7052 -x 70 mi am 7 8.48 = Fox 25/7.52-x) = 70x TT 8-488258 7.52- 8.48x 25% 1594. 24 - 212 x=702 282x = $94.24 > x=5065g extracted in 1st Extraction. Akx 34 €х на сhест , +1| (253-565) 0 0 эчаміс Сатур олио present in Aqueous layer.

- 1.87g of organic compound still 1st extraction present in Aqueous layer. let's let's say "y" gram as affer Organic compound extracted and extraction. → 8.48= y g 25ml of ether XM almos (1.87-4 g to ml of water xy ghnes 8.48 = 70 y 25(1:87 - y) - 8.48 x 1087425 -8.48x25y = fog 396.44 = (to +212) y → 2824 = 396.44 1.405 g Mass of extracted organic in and compound Extraction. Mass of organic compound still after and left in Aqueous layer extraction = 1.87 1.405 = 0.4659 = 0.465g Organic Compound still layer after two extraction. present in the aqueous