Question

What will be the free energy released when the system reaches equilbrium from starting pressures PNO = .14 atm, PO2 = .13 atm, and PN2O3 = 2.65 atm

4NO(g) + O2(g) $\leftrightarrow$ 2N2O3(g) Kp = 3.6 * 10¹¹

Temp = 298K

Answer 1

solution As per given in the question, for the reaction ч No4) + (9) — & өз у К-3,4 х 14'q+ 3 3/ @ for the seaction Przez a 265am og Nag Pro zoluadh - Protx Por po2 = 0.13am az (2165]- - 1,418104. 1011474x(0:13] from Thermodynamics 4Gz 46° +21303 R Toges But Ago=-2.353 R T log ke a from Equi, (ii) e (iii) 44= -2.303 RT log kp t 2:33 RT log 9 = 2.33R7 ( - lagret A9= 2334 8.34 629? [-lag. « Alo" + bag livsed.] logo 4G =-42, 208 kJ