Question

Construct a Crystal Field Splitting diagram for each of the following and state how many unpaired electrons in each:

Zn²⁺

Cu²⁺

Fe²⁺

Co²⁺

Mn²⁺

Answer 1

As, nothing has been specified about conditions, we will assume all to be high spin systems and octahedral field splitting.

Zn2+ do system . 1L TV 11 11 11 11 h : 1 I IV No. of unpaired electrons = 0 + 2 Cut? → do system TV1 AL1L 4711 11 1 11 No. of unpaired electrons= 1 feta » do system 1291 FI 16 I No. of impaired electrons = 4 1 1 I Cot? → dy system 71 74111 ith 16 1 No. of cimpaired electrons = 3 - Mnt? → ds system 11 11111! 1.1.11 No. of unpained electrons = 5

Zn2+ do system . 1L TV 11 11 11 11 h : 1 I IV No. of unpaired electrons = 0 + 2 Cut? → do system TV1 AL1L 4711 11 1 11 No. of unpaired electrons= 1 feta » do system 1291 FI 16 I No. of impaired electrons = 4 1 1 I Cot? → dy system 71 74111 ith 16 1 No. of cimpaired electrons = 3 - Mnt? → ds system 11 11111! 1.1.11 No. of unpained electrons = 5