Question

Question #6 Given the following logk values SO2- + H+ + S + H2O logk-6.03 130.2- + H+ + = H,S() + H20 logk 5.25 SO2- + H+ + = HS + H2O logk-4.25 Sw) + H+ +e- = H,Sw logK-2.89 H+ + = H2(8) logk-0.00 pka2 H2SO4 = 2.00 (note pka is completely strong for sulfuric acid) pka1 H2S = 7.00 (you can ignore pka2). label the pe-pH diagram and determine the equations of the 7 lines. a 0 -10 6 3 4 PH

Answer 1

Ih such diagramme : a horizontal line separates species related by electron transfer only, a vertical line
separates species related by proton transfer only, and sloped lines separate species related by both
electron and proton transfer.

if n = 1 ( No. of electron transfer )

pe + pH = logK

Equations for lines :

1. HSO4- (aq) <===> SO42- (aq) + H+ (aq) (pKa = 2.00)   ===> at pH ~ 2

2. H2S (aq) <===> HS- (aq) + H+ (aq) (pKa = 7.00)     ====> at pH ~ 7

3. 1/2 S + H+ + e <==> 1/2 H2S

4. 1/6*SO42- + 4/3*H+ + e <==> 1/6 S + 2/3*H2O

Question #6 Given the following logk values SO2- + H+ + S + H2O logk-6.03 130.2- + H+ + = H,S() + H20 logk 5.25 SO2- + H+ + = HS + H2O logk-4.25 Sw) + H+ +e- = H,Sw logK-2.89 H+ + = H2(8) logk-0.00 pka2 H2SO4 = 2.00 (note pka is completely strong for sulfuric acid) pka1 H2S = 7.00 (you can ignore pka2). label the pe-pH diagram and determine the equations of the 7 lines. 10 H504 SO4^2- S H2S HS- 8 -10 - 2 4

7. 1/6* HSO4- + 1/3*H+ + e <==> 1/6 S + 2/3*H2O