Question

1) Use both the ionic and covalent counting systems as was done in the examples in class to give electron counts for the metal and each type of ligand. Use these to determine the total electron count for these organometallic compounds (watch for oxidation state of cationic complexes! Also, not all are 18 e*): a) b) H3cFe.co co

Answer 1

Solution:

Br -Br Covalent method: - Valence e- of zo = 4 Electront count Bor Br = 102=2 Electron count = 5x2 for o u = 10- Cas heptacity = 5) Electron count = 4+2 + 10 = 16 Sol Total Ionic method. oxidation State of Zr= a -1-1-1 -1 = 1xc=ty 0 as Bro & ad Now, Electron count = 20+4 =0 2 B10 = 2X 2 =4 2007 = 6 X 2=12 Total electron count =o+ 4+12) = 16

Tonic Mothony Election Count Covalent Method tehlico Electron count Co Co=2 O =5 fe = 8 -CH₂ CH₂ = 1 r Total electron Count 2x2 +5 +1+8=18 a SCH, CH₂=2 fet? - 6 oxidate State fe=42 x-1-1= 0 Total Electron Count = 2x2+61 +2 +6 PEDRO T= 18 Phypn ph Lppha A Till Covalent Method (Electron count) 3 PPh ₂ =2 = 4 6 21 Co=2 7 40 H = 1 Rh=9 Total e count = 8+241 + 9=18 Ionic Methode oxidate state Rh = x-1=0 Election Counti x = D Pphz = 2x3=6 - Total e Counte y co - 2 1 6+2+2+8=181 OH = 2 l Rht = 8)

Covalent Method (Electron count) R$ 8-17 -NH₂ - NH2 = 2 Total Electron Count = - +1+2 +6 = 163) Ionic Method: oxidation State = x+(-1)7-1 = + 9 (Electron Count) I Ny Nity = 4 Total e Count - 6+244 + 4 = 16 Ruth & 8-4 = 4

Electron count for (a) to (d) has been founded.

As per Chegg's policy, I've solved first 4 parts.

Hope, it helps. :)