Question

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Use both the ionic and covalent counting systems as was done in the examples in class to give electron counts for the metal and each type of ligand. Use these to determine the total electron count for these organometallic compounds (watch for oxidation state of cationic complexes!  Also, not all are 18 e‐ ):

Answer 1

- Q Br zo = 4 - -BY 2Br = 2 Covalent method ionic methol 12+ = 2Br = 4 2Cp = 10 200 = 12 total ě - 16 - To - - count 1 Fe2+ = 6 200 = 4 te H₂CV ico Fe = 8 200 = 4 "Co -CHCH₂ = 1 Cp = 5 total ě = 18 I Å = 6 CH₂ CH = 2 18 count 1 Rh = 9 Rht = 8 Phap camph - PPha 3Ppha = 6 3Pph3 = 6 co=2 Phap co 1 1 co=2 H =1 totale = 18 count 18 Rut = at = 2 7 @o0 R = 8 C1 = 1 NH2 NM2 LN Hz - = 4 TNH₂ = 4 LNM, total e = 19 count Co - 9 zo = 6 Het Cot = 8 3 co = 6 & t = 4 18 Catts = 3 total e = 18 count

CH3 Fe (0) = 8 Fe=8 4 N = 8 / i 40 = 8 1 16 HC, totale = 16 count Hooc COOH Pd = 10 of= 3 I pd4* = 6 1 BE = -a- 74 totallé 14 4 count 1 0 = 6 9 Os = 8 a=1 ci = 2 charge = -1 totale = 18 count