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How will the pressure change if a sample of an ideal gas in a rigid 2.0 L container initially at 250 °C is cooled to -142 °C?
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Answer #1

Ti = 250 oC
= (250 + 273) K
= 523 K

Tf = -142 oC
= (-142 + 273) K
= 131 K

Now use:
Pf/Pi = Tf/Ti
Pf/Pi = 131/523
Pf/Pi = 1/4

Answer: option 1

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