4. What is the potential of a half-cell consisting of Zinc electrode in 0.01M Znsos solution...
In a copper-zinc voltaic cell, one half-cell consists of a ZnZn electrode inserted in a solution of zinc sulfate and the other half-cell consists of a CuCu electrode inserted in a copper sulfate solution. These two half-cells are separated by a salt bridge. At the zinc electrode (anode), ZnZn metal undergoes oxidation by losing two electrons and enters the solution as Zn2+Zn2+ ions. The oxidation half-cell reaction that takes place at the anode is Zn(s)→Zn2+(aq)+2e−Zn(s)→Zn2+(aq)+2e− The CuCu ions undergo reduction...
A voltaic cell contains two half-cells. One half-cell contains a zinc electrode immersed in a 1.00 M Zn(NO3)2 solution. The second half-cell contains a titanium electrode immersed in a 1.00 M Ti(NO3)3 solution. Zn2+(aq) + 2 e− → Zn(s) E⁰red = −0.762 V Ti3+(aq) + 3 e− → Ti(s) E⁰red = −1.370 V (a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell. _____ V (b) Write the overall balanced equation for the...
Calculate the half cell potential of the hydrogen electrode in a solution of pH = 5, 6, 7, 8, and 9 and at partial pressure of hydrogen of 0.5 + 0.8 atm, respectively at 25 degree C. Cell notation: Pt/H_2/H^+. Plot the half cell potential as a function of pH at above partial pressures of hydrogen. 2H^+ + 2e^- rightarrow H_2 e^0_H^+/H_2 = 0V
1-One-half of an electrochemical cell consists of a pure Zinc electrode in a solution of Zn2+ ions; the other half is a Lead electrode immersed in a solution of Pb2+ solution. The half-cell potentials for Zinc and Lead are -0.763 V and -0.126 V, respectively. (a) If the cell is a standard one, write the spontaneous overall reaction and calculate the voltage that is generated. (b) Compute the cell potential at 25oC if the Zn2+ and Pb2+ concentrations are 10-2...
A galvanic (voltaic) cell consists of an electrode composed of zinc in a 1.0 M zinc ion solution and another electrode composed of gold in a 1.0 M gold(III) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C. Standard reduction potentials can be found here.
4.In a electrochemical cell consisting of a silver electrode in a solution of AgNO3 and a gold electrode in a solution of Au(NO3)3 at standard conditions, the correct cell potential is 0.70 V b. 2.30 V 0.90 V d. -0.90 V 5. Predict which of the following reactions would exhibit an increase in entropy based on the nature of the reactants and products. 2H2(g) + O2(g) → 2H2O(g) 2NO2(g) → N2O4(g) H+(aq) + F-(aq) → HF(aq) BaF2(s) → Ba2+(aq) +...
Help! Electrochem questions: (1) An electrochemical cell consisting of a cadmium electrode immersed in a solution of 0.001M cadmium (II) nitrate, and a hydrogen electrode. The hydrogen electrode contains a solution of hydrogen cyanide. The pressure of the hydrogen gas is 1 atm. What is the concentration of the acid when there is measured a potential of 0,220V at 25 ° C. (2)A galvanic cell is composed of copper / copper ion solution (0.1M) on the one hand, and a...
Calculate the cell potential (E) for the half-reaction of a silver-silver chloride reference electrode (E = 0.222V) at 25 °C that contains KCl with a clºactivity (A) of 1.29. E = For the same type of reference electrode, determine the activity of C1 when the half-cell potential (E) is 0.266 V at 25 °C. A=
A cell consisting of a saturated calomel electrode and a lead electrode developed a potential of -0.4706 V when immersed in 50.00 mL of a sample. A 5.00 mL addition of standard 0.02 M lead solution caused the potential to shift to -0.4490 V. Calculate the molar concentration of lead in the sample.
One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining