Question 3 (2 points) Based on the thermochemical equation 2 C4H10 + 13 02 → 8...
Question 1 (2 points) Based on the thermochemical equation 2 C4H10 + 13 O2 8 CO2 + 10 H20 AH = -5316 kJ, if (7.47x10^1) g of C4H10 (MM = 58.14 g/mol) reacted with excess oxygen, how many kJ of heat would be released? NOTE: The word "released" means that NO NEGATIVE SIGN IS NEEDED in your answer. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any...
Based on the thermochemical equation 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O ΔH = -5316 kJ, if (5.81x10^1) g of C4H10 (MM = 58.14 g/mol) reacted with excess oxygen, how many kJ of heat would be released? NOTE: The word "released" means that NO NEGATIVE SIGN IS NEEDED in your answer. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. PLEASE...
Question 4 (2 points) What is the value of AH in kJ for the overall reaction: 4 NO + 6 H20 + 4 NH3 +5 O2 given these reaction steps? 1. N2 + O2 + 2 NO AH = (1.97x10^2) kJ II. 2 NH3 + N2 + 3 H2 AH = (8.870x10^1) kJ III. 2 H2O → 2 H2 + O2 AH = (4.7900x10^2) kJ Enter your answer in scientific notation with 3 sig figs. Do not include any units...
How many grams of Mg(NO3)2 (MM = 148.33 g/mol) would it take to lower the freezing point of (4.95x10^2) grams of water by 4.00°C? The freezing point depression constant of water is Kp = 1.86°C/m. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: X10 Answer
Given the following equation: 2 C4H10+ 13 02 →8 CO2 + 10 H20 How many grams of C4H10 are needed to produce 36.20 grams of H20? 8 C4H10
An aqueous solution has a mole fraction of solute of (3.660x10^-2). The density of the solution is (1.20x10^0) g/mL and the solute has a molar mass of (8.3800x10^1) g/mol. What is the Molarity of solute of this solution? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer
At an unknown temperature a solution made of (5.180x10^0) g of a non-volatile solute dissolved in 100.0 g of water has a vapor pressure of (5.54x10^1) mm Hg. What is the vapor pressure of pure water (in mm Hg) at this unknown temperature? The molar mass of the solute is (4.620x10^1) g/mol. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is...
11 12 13 Combustion of glucose occurs as shown below: 2C6H12O6 (s) + 12 02 (9) 12 H20 (1) + 12 CO2 (9) Apply Hess' law and calculate the AH for the above reaction. Useful thermochemical data are given below. Just type the final numerical answer with proper sign and sig figs. C (s, graphite) + O2 (9) - CO2 (9) AH = -393.50 kJ H2O (9) H2(g) + 1/2 02 (9) AH = +241.82 kJ H20 (0) - H20...
When (8.61x10^1) g of a non-electrolyte is dissolved in (5.3100x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to...
Question 1 (2 points) ✓ Saved The heat capacity of a metal is 0.45 J/g °C. How many Joules of heat would it take to raise the temperature of (4.9400x10^1) g of this metal from (5.69x10^1) to 95°C? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculation. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Jxzo o Answer