Given the following equation: 2 C4H10+ 13 02 →8 CO2 + 10 H20 How many grams...
Given 2 C4H10 + 13 O2 =====> 8 CO2 + 10 H20, how many liters of H20 are needed for 18.0 liters of C4H10? a. 9.00 Liters b. 90.0 Liters c.5.00 Liters d. 27.7 Liters
Question 3 (2 points) Based on the thermochemical equation 2 C4H10 + 13 02 → 8 CO2 + 10 H20 AH - -5316 kJ, how many grams of C4H10 (MM = 58.14 g/mol) would have to react in order to release (7.44x10^4) kJ of heat? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest...
Name: Class: HW Chapter 3: Stoichiometry 1. Given the following equation: 2 C4H10 + 13 02 + 8 CO2 + 10 HO Write the following molar ratios: a. C4H10 02 H2O 1 C4H10 CO2 C4H10 H2O 2. Given the following equation: 2 KClO3 + 2 KCl + 3 O2
Calculate how many grams of butane (C4H10) form when 1.11 g of O2 reacts completely given the following equation: 2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)
Based on the thermochemical equation 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O ΔH = -5316 kJ, if (5.81x10^1) g of C4H10 (MM = 58.14 g/mol) reacted with excess oxygen, how many kJ of heat would be released? NOTE: The word "released" means that NO NEGATIVE SIGN IS NEEDED in your answer. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. PLEASE...
Question 1 (2 points) Based on the thermochemical equation 2 C4H10 + 13 O2 8 CO2 + 10 H20 AH = -5316 kJ, if (7.47x10^1) g of C4H10 (MM = 58.14 g/mol) reacted with excess oxygen, how many kJ of heat would be released? NOTE: The word "released" means that NO NEGATIVE SIGN IS NEEDED in your answer. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any...
1. [12.7 g C4H10] Butane, C4H10, is a common fuel. How many grams of butane can be burned by 45.4 grams of oxygen? 2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O 2. [350. g NH4NO3] The fertilizer ammonium nitrate (NH4NO3) can be made by direct combination of ammonia with nitric acid: NH3 + HNO3 ----> NH4NO3 If 74.4 grams of ammonia (NH3) is reacted with nitric acid, how many grams of ammonium nitrate can be produced?...
Question 2 of 12 Determine the number of grams of C4H10 that are required to completely reac produce 8.70 mol of CO2 according to the following combustion reaction: 2 C-H10(g) + 13 02(g) → 8 CO:(g) + 10 H2O(9) х DUNT ADO FACTOR ANSWER RESET 2.18 0.0374 4.35 8.70 18.02 44.01 58.14 13 8 208 10 6.022 x 10" mol C.H. 126 2 g CO g 02 ich here g H20 g CH30 mol CO2 mol O2 mol H
Question 10 of 14 How many grams of CO2 can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C4H10 (g) +13 O2 (g) 8 CO2 (g) +10 H2O (g) 1 2 3 6 C 7 +/- x 10 R E W
QUESTION 1 H20 is balanced, the coefficient in front of the O2 is CO2 02 When the equation C2H4 1 2 3 4 QUESTION 2 How many grams of N2 is needed to fully react with 9.0 grams of H2 in the equation 2 NH3 3H2 N2 7.0 g 14 g 21 g 42 g OOO QUESTION 1 H20 is balanced, the coefficient in front of the O2 is CO2 02 When the equation C2H4 1 2 3 4 QUESTION...