A bass clarinet can be modeled as a 120-cm-long open-closed tube. A bass clarinet player starts playing in a 20∘C room, but soon the air inside the clarinet warms to where the speed of sound is 352 m/s.
What is the change in frequency?
L = length of the pipe = 120 cm = 1.20 m
T = room temperature = 20
V = speed of sound at room temperature = 331.4 + 0.6 T = 331.4 + 0.6 x 20 = 343.4 m/s
frequency at T = 20 is given as
f = V/(4L) = 343.4 /(4 x 1.20) = 71.5 hz
at V' = 352 m/s
frequency is given as
f' = V'/(4L) = 352/(4 x 1.20) = 73.3 hz
Change in frequency = f' - f = 73.3 - 71.5 = 1.8 hz
A bass clarinet can be modeled as a 120-cm-long open-closed tube. A bass clarinet player starts...
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