Please give explanations B 3) Given: H2S(g) + 02(g) - H20 (liq) + SO2(g) AH =...
5. Given the following data: 2 H2(g) + O2(g) → 2 H20 (1) AH° = -571.6 kJ N,Os (g) + H20 (1) ► 2 HNO (1) AH = -76.6 kJ N2(g) + 3 O2 (g) + H2(g) → 2 HNO, (1) AH = -348.2 kJ a. Calculate the AHⓇ for the reaction: 2 N2 (g) + 5 O2(g) → 2 N2Os (g)
A chemist measures the enthalpy change AH during the following reaction: 8 SO2(9) 16 H2S(g) AH=-1863. kJ 3 Sg(s) + 16 H,20) Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. AH Oto reaction E726. kJ 16S0, (8) +32H,S () -- 6s,) +32H20 () 1863. kJ 3s,() +16H,O()8So, (e)16H,s() 5589. kJ 9s,()48H,0()24SO, (s) +48H,S (g)
I know the right answer is -233.8 but can someone please show the steps to get there? Thanks! Question4 10 10 pts The value of [delta)Ho for: 2 H2S (g) +SO2 (g) 3 S (s) + 2 H20 () is: H2 (g) 1/2 02 (g)H2O) [deltajH°-285.8 kJ H2 (g)S (s) > H2S (g) [delta)H°-20.5 kJ S (s) +O2 (8) >SO2 (g) (deltajHo --296.8 kJ +603.1 k 454.9 k +233.8 k 233.8 kJ -603.1 kJ
(1) Consider SO2 (g) + 2H2S(g) = 3(g) + 2H2O(1) AH : (i) SO2 (g) = -296.8 KJ/mol (ii) H2S (g) = -20.4 KJ/mol (iii) H20 (1) = -285.84 KJ/mol AH for the above reaction is: (a) 234.08 KJ (b)-234.08 KJ (c) 31.36 kJ (d) -31.36 KJ (e) None (2) The above reaction is (a) Endothermic (b) Exothermic (c) entropic (3) in k = Ae Ea/RT, Ea is (a) Activation Energy (b) 8.314 J/mol.K (c) Rate constant (4) In a...
17. Given the flloving reactions H20 (1) H20 (g) 2 H2 (g) + 02 () 2 H20 (g) AH 483.64 kJ AH-44.01 k the enthalpy for the decomposition of liquid water into gaseous hydrogen and oxygen 2 H20 1) 2 H2 (g) + 02(8) kJ. A)-395.62 B) -527.65 C) 439.63 D) 571.66 E) 527.65
Given the following data: S(s) + 02(8) -> SO3(g) AH = -395.2 kJ 2SO2(g) + O2(g) + 2503(g) AH = - 198.2 kJ Calculate AH for the reaction: S(s) + O2(g) SO2(g) +296.1 kJ -494.3 kJ -296.1 kJ 0 -197.0 kJ -593.4 kJ
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data
Calculate the value of AH° for the reaction 2 C2H2 () + 502 () 4002) + 2 H20 (1) given the following thermochemical equations: AH° = - 242 kJ AH° = - 394 kJ H2(g) + 4202) → H20 (8) C(s) + O2(%) + CO2(8) 2 C(s) + H2(g) → C2H2 (6) H20 () → H30Ⓡ AH° = +227 kJ AH° = +44 kJ TO - 907 kJ 0 - 2602 kJ 0 - 2514 kJ - 1694 kJ
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
Hess's Law Given the following data: C2H2(g) + 5/202(9) + 2002/9) + H20(1) AH' = -1300.0 kJ CO2(g) + C(s) + O2(g) AH° = 393.5 kJ 2C(s) + H2(g) C2H2(g) AH° = 227.0 kJ Calculate AH for the reaction H2(g) + 1/202(9) — H20(1) Submit Answer Tries 0/5