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17. Given the flloving reactions H20 (1) H20 (g) 2 H2 (g) + 02 () 2...
6) Given the following reactions H20 (1) H20 (8) AH = 44.01 kJ AH = -483.64 kJ 2H2 (8) + O2(g) +2H20 (g) the enthalpy for the decomposition of liquid water into gaseous hydrogen and oxygen 2H20 (1) +2H2 (g) + O2(g) _kJ.
Part C Given the following reactions 2H2 (9) + O2(g) → 2H20 (9) AH = - 483.64 kJ 2H20 (1) ► 2H2(g) + O2 (9) AH = 571.66 kJ Calculate the enthalpy for the condensation of water vapor to liquid, given by this reaction: H2O(g) + H20 (1) +44.01 kJ +88.02 kJ 0 -44.01 kJ -88.02 kJ Submit Request Answer
19. Which of these reactions correspond to the enthalpy of formation (AH;°) 3 C2H2(g)H2(g)- CH(g) H2(l)02()H20(l) Cdiamond02 (g) - CO2(g) D) A) B) C) H20 (g)H20(l) Na(s) C(g) NaCl(s) E)
15. Given the following reactions and their associated values of AH, what is the value of AH for the equation shown below? 2 H200 → 2 H2(e) + O2(6) H200 H2O) 2 H2(g) + O2(g) → 2 H2O) AH - 44.01 kJ AH = -483.64 kJ
Which of the following statements is false concerning the reaction of hydrogen gas and oxygen gas given below? H2(g)+1/2O2(g)>H2O Which of the following statements is false concerning the reaction of hydrogen gas and oxygen gas given below? H2(g) +029) - H20(1; AH = -285.8 kJ Select one: a. For the reaction H2(g) + O2(g) - H2O(g), AH is not equal to -285 b. If the equation is reversed, AH becomes +285.8 kJ. If the equation is multiplied by 2, AH...
Please give explanations B 3) Given: H2S(g) + 02(g) - H20 (liq) + SO2(g) AH = -562.3 kJ 1/8 Sg(s) + O2(g) - SO2(g) AH° = -297.0 kJ H2(g)+102 - H20 (liq) AH -266.9 kJ Compute AHⓇ for H2(g) + 1/8 S8 (s) - H2S(g) in kJ. A) 20.5 kJ (B) 562.3 kJ C) 276.6 kJ D) 265.3 kJ E) -1.6 kJ
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data
1) Enthalpy changes for the following reactions can be determined: AH=-91.8k N2(g) + 3 H2(g) → 2 NH (B) 4 NH(B) + 5 O2(g) → 4 NO(g) + 6H2O () H2(g) + O2 (g) → H20 (8) AH = -906.2 kJ AH = -241.8 kJ What is the enthalpy change for the following reaction? % N2(g) + O2(g) → NO(g) 2) Consider the following thermochemical equation: 2CH.(g)+70:(g)4CO2(g)+6H,0(1) AH--3120 kJ If 2.4 L of ethane (C2H6) at STP are reacted with...
5. Given the following data: 2 H2(g) + O2(g) → 2 H20 (1) AH° = -571.6 kJ N,Os (g) + H20 (1) ► 2 HNO (1) AH = -76.6 kJ N2(g) + 3 O2 (g) + H2(g) → 2 HNO, (1) AH = -348.2 kJ a. Calculate the AHⓇ for the reaction: 2 N2 (g) + 5 O2(g) → 2 N2Os (g)
HQ11.43 Homework Answered For the reaction of H2(g)+1/2 02(g) H20(g), AH° is -285.82 kJ. What is AHo for the reaction 2H20(g) -- > 2H2(g) + 02(g)?| HQ11.45 Homework Unanswered Using the first equation in HQ11.43, how grams of 02(g) will be needed to produce 55.0 kJ of heat if reacted in excess H2(g)? Report answer in grams without units Numeric Answer: