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Part C Given the following reactions 2H2 (9) + O2(g) → 2H20 (9) AH = -...
6) Given the following reactions H20 (1) H20 (8) AH = 44.01 kJ AH = -483.64 kJ 2H2 (8) + O2(g) +2H20 (g) the enthalpy for the decomposition of liquid water into gaseous hydrogen and oxygen 2H20 (1) +2H2 (g) + O2(g) _kJ.
Part 2 Consider the combustion of ethanol in the engine cylinder of a vehicle. The process releases heat) and the resulting work (w) drives the vehicle. If the chemical reactants in the cylinder are considered the system what do you expect the signs of and w for the process? Og() O9w+) OW) Og() w Suomi Rust Answer Part Given the following reactions 2H, (a) + O2(g) → 2H,0 () AH-483 64 2H20 (1) ► 2H2(g) + O2(a) AH 57166 kJ...
17. Given the flloving reactions H20 (1) H20 (g) 2 H2 (g) + 02 () 2 H20 (g) AH 483.64 kJ AH-44.01 k the enthalpy for the decomposition of liquid water into gaseous hydrogen and oxygen 2 H20 1) 2 H2 (g) + 02(8) kJ. A)-395.62 B) -527.65 C) 439.63 D) 571.66 E) 527.65
QUESTION 7 AH® - -560 kJ Look at this reaction: 2H2(g) + O2(9) --> 2H20(1 Which one of the following statements is true? Heat is absorbed during the reaction The reaction is endothermic The enthalpy change is positive This reaction is exothermic
15. Given the following reactions and their associated values of AH, what is the value of AH for the equation shown below? 2 H200 → 2 H2(e) + O2(6) H200 H2O) 2 H2(g) + O2(g) → 2 H2O) AH - 44.01 kJ AH = -483.64 kJ
Given the standard enthalpy changes for the following two reactions: (1) N2(g) + O2(9)— 2NO(g) AH = 181.8 kJ (2) N2(g) +202(9)—2NO29) AH° = 66.4 kJ what is the standard enthalpy change for the reaction: (3) 2NO(g) + O2(9) *2NO2(9) AH° = ? Submit Answer
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and their AH values: | C(s) + C(s) + H2(g) + Express the enthalpy in kilojoules to one decimal place. 2H2 (g) 2Cl2(g) Cl2(g) + CH4(g), + CCL(g), + 2HCl(g), AH = -74.6 kJ AH = -95.7 kJ AH = -184.6 kJ %AM * o aj ? AH,,n= Submit Request Answer
Consider following chemical reactions: 1) CH2(g) + 202(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) → 2C0(9) 4) 3C(s) + 2H2O(l) → CH4(g) + 2CO(g) H2O(l) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
For the reaction: 2H20(g) = 2H2(g) + O2(g) Kc = 2.40 x 10-3 at a given temperature. At equilibrium, it is found that [H20] = 0.290 M and [H2] = 1.80 x 10-2 M. If the reaction is run in a 8.50 L container, how many moles of O2 are present at equilibrium? moles O2 Tries 0/99 Submit Answer