How many of energy are involved in heating 45.0 g of Substance X (MM 125.00 g/mol,...

Question

Question

Answer 1

Answer #1

As phase of Substance X is not changing here. So, we will use Q = mcDT. (Where DT is difference of temprature)

Here, DT = (50 - (-10)) oC = 60oC

Heat involved in heating 45g of X = mcDT

= 45g x 3.4 J/(g oC) x 60oC

= 9180 J

= 9.18 kJ

Answer 2

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