Question

10. When a 3.25 g sample of chromium, initially at 27.3°C, is placed in 87.6 g of water initially at 56.2°C, the temperature changes. What is the final temperature of the metal and water?

Answer 1

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liven, m = mass of chromium = 3.25g T = temperature of chromium 27.3°C m₂ = mass of water = 87.6 g 2 = temperature of water = 56.2°C T = fine cmperature of equilibrium = ? Also, AL S = specific weat capacity of = 0.450 5/9°c - chromium 32 = specific hear capacity of = 4.1845/8 c 1 warer The bemperature of chromium will increase and water will decrease. . By calosiemerry we can write mis, (T-T,) =mes, (T2- ( nean gain = near lous) As chromium will gain heat willd and its sempetanice will increase and water will lose heat and its temperature will deisease. Putting values en egn 3.259 x 0.4509/9 °C X(1–27.3°C) = 87.69 x 4.1845/9 °cx (56.2 -T) upon calculation, we get T = 56.1°c Scanned with CamScanner