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PART A is already solved. It is provided for context for you :) PART A: If...

PART A is already solved. It is provided for context for you :)

PART A: If you have a initial conc. 0.10M NH4NO2, make an ICE table, solve for concentration of NH4+, NO2-, NH3 and HNO2.K1 value is 1.23e-6

NH4+NO2<=>NH3+HNO2

[NH4] and [NO2] both are 9.99e-2 M

[NH3] and [HNO2] were found to be 1.11e^-4 M

PART B (the part I need help with): Using the values you found in part A (conc. of NH4 and NH3), find the value of the concentration of H3O+.

NH4+(aq)+H2O(l)<=>H3O+(aq)+NH3(aq)

Ka value is 5.6e^-10

Thank you in advance!

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Answer #1

Nht Hole) & Hot + NH, (aq) k=526 X10 ki CH3 0#][rins] 5.6810-10 = [H, O*] (111x1004) (9.99x10-2) [H3O+] = 50.4x108 M CS Scann

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