65.0 mL of 0.125 M NaOH is titrated with 0.315 M HCl. What is the pH...

Question

Question

65.0 mL of 0.125 M NaOH is titrated with 0.315 M HCl. What is the pH after the addition of 30.0 mL of HCl?

Please show clear work and clarify where all numbers came from and equations used.

Answer 1

Answer #1

Member of moles of OH = molosity x volume -0.008195 Member of moles of HCl = 0.315x0.030 50.00945 tre + NaOH Nace fH₂O 0.0094

Answer 2

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