65.0 mL of 0.125 M NaOH is titrated with 0.315 M HCl. What is the pH...

Question

Question

65.0 mL of 0.125 M NaOH is titrated with 0.315 M HCl. What is the pH after the addition of 30.0 mL of HCl?

Answer 1

Answer #1

moles of NaOH = 0.125 x 65 x10 3 = 8.125810 mol. moles of HCM = 0.315x 30 10-3 = 9.45410-3 mon moles of her remaining after n

Answer 2

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