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Lead(II) azide decomposes as shown below: Pb(N3)2(s) → Pb(s) + 3 N2(g) Some lead(II) azide decomposes...

Lead(II) azide decomposes as shown below:

Pb(N3)2(s) → Pb(s) + 3 N2(g)

Some lead(II) azide decomposes and the gas is collected over water. 675 mL of gas is collected at 30.oC and 795 Torr. How many moles of nitrogen gas were produced? The vapor pressure of water at 30.oC is 31.8 Torr.

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Answer #1

Ptotal - Pho + PN PN = 795 torr - 31.8 torr - 76.3.2 tory Now, PV = nRT P = Press are = 763.2 torr V = Volume = 675 ml = 0.67

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