Option B is correct
When ribosome, poly U , tRNA and amino acid were mixed , short sequence of phenylalanine amino acids were synthesized.
As we can see lines in pink and green colour there is no phenylalanine polymerization present because there is no poly U sequence provided . This means poly U sequence must be present in order to carry out phenylalanine polymerization.
Rest of the above lines shows phenylalanine polymerization in presence of poly U sequence up to 7 phenylalanine amino acids which is actually short peptide.
Line at 37 is optimum temperature, shows rapid synthesis of short peptide
When temperature increases slowly ( yellow) polymerization increases slowly, reached up to 7 no of phenylalanine sequence.
So option B is most suitable answer
phe 24 with poly- U ONO enylalanine polymerized no poly-V URI 0 0 10 20 30...
0 no poly U 240 0 0. 0 999 0 10 20 30 40 50 60 70 80 time (min) How do the data in Figure 2.21A support linking the codon UUU to the amino acid phenylalanine? These data support that you need a codon of threenucleotides to code for 1 amino a When ribosomes, poly-u, tRNA, and amino acids were mixed, short sequences of phenylalanine amino acids were synthesized. When ribosomes, mRNA, TRNA, and phenylalanine were mixed, short sequences...
C++: Translating mRNA sequence help
Homework Description Codon 1 You are working in a bioinformatics lab studying messenger RNA (mRNA) sequences. mRNA is a sequence of the nucleotide bases (Adenine, Cytosine, Guanine, and Uracil) that conveys information stored in DNA to Ribosomes for translation into proteins. The bases in the sequences are denoted by the first letters of the nucleotide bases (e.g. A, C, G, and U). A sequence of mRNA is made up of hundres to thousands of nucleotide...
C++ Help
Task B: Translation
While
a nucleotide is the basic unit of information, three nucleotides,
or codon, is the basic unit of storage. The reason
for this is that each gene codes for a protein, and all proteins
are made from 20 amino acids. Recall that there are 4 different
bases that make up dna. Thus, three bases can encode for 4x4x4 = 64
different symbols. Two base pairs can only encode for 4x4 = 16
symbols, which is...