Physics college
A cylindrical rod of uniform density is located with its centre at the origin and its axis along the axis. It rotates about its centre in the xy plane, making one revolution every 0.02 s. The rod has a radius of 0.02 m, length of 0.2 m, and mass of 5 kg. What is the rotational kinetic energy of the rod?
Homework Answers
KErot = 1/2 * I * w2
I = MR2/4 + ML2/12
I = 5*0.022/4 + 5*0.22/12 = 0.017166
w = 2π/T = 2π/0.02
Therefore, KErot = 1/2 * 0.017166* 4π2/0.0004 = 847.141 J
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