can
someone explain how they calculated twist T=-60 for 940 turns?
U L LUIC llave superhelix...
U L LUIC llave superhelix densities of about 0.06. To get an idea of what this means, consider a hypothetical DNA mol- ecule of 10,500 bp, which is in the solution B form, with 10.5 bp/turn. Then L, is 10,500 bp/(10.5 bp/turn), or 1000 turns. Each DNA strand crosses the other 1000 times in the relaxed circle. If the topoisomerase DNA gyrase (see page 1055) twisted the molecule to a superhelical density of -0.06, then L = -0.06 Lo, or L = -60. This change could be accommodated, for example, by the helix axis writhing about itself 60 times in a left-handed sense, which would correspond to AW = -60, T = 0; the molecule would have 60 left-handed superhelical turns. Alternatively, the twist of the molecule could change so that it had 940 turns in 10,000 bp (T = 940) or ange so that .cd superhelicspond to Am