Question

You are still interested in the enzyme happyase, which catalyzes the following reaction: HAPPY = SAD Previously, you determined that kcat = 400 s and Km = 10 M for your sample of happyase. Further research shows that this happyase sample was actually contaminated with a reversible inhibitor called ANGER. When ANGER is fully removed from the happyase preparation and [Eltotalis 4 nM, the measured Vmax is increased to 4.8 umes-1 and the measured Km is now 15 MM. Use this information in the following questions. (Hint: What we are saying is that the kinetic parameters from the prior questions were actually apparent keat and Km values with inhibitor present and the values given in this question are with no inhibitor.) Question 8 2 pts For the inhibitor ANGER calculate a

Answer 1

Иеру 2 SO In presence of inhibitor ANGER keat = 40051 hits km - 10M i es In ANGER absence of inhibitor Vimax - 4.8 uMs7 Ky = 15 uM Giren: [E3 rotal = 40 Vmax (in presence of inhibitor) - Vmax app. Vimax app. = keat & LEIJER - 400 x 4 B. - 16000mst -1.6 umst = NAPAPPPPPPPP i Apparent KM & Uman, boter have decreased in presence of the inhibitor ANGER. Since both ky & Vmax Values have changed & decreased, ist indicates mired inhibition.

8. For the inhibitor ANGER For mined max inhisition: app - max а К» аре к қы 2 бие чег Муах - - - Э/w'. 3/ . . Ky app 0 - LKM - 2

x=2 4 &= 31 Moose to. In competitive inhibitor's presence KM increases but Vmax remains constant (only & is greater than 1). In non competitive Vmax decreases but (a = a ). inhibitor's presence. ky remains constant In uncomperitive inhibitor's presence Vmax increases but KM decreases. (only & changes & is greater than 1). In mixed inhibitor's presence Vmax decreases with either increase or decrease in Km ( botw & & a values are affected and are greater than 1). (ata). . The inhibitor ANGER gives two Values for a da, this it is a mixed inhibitor.

11. Ki=? [I] = 200uM LE] Total 4am К; ел 4 . inhibitor constant from the We can following calculate ki formula a a: 1+ [1] ki & ki + [I ki - ki + [I] since 2=2 te w int ki= kit 200 Rad now QUA student wat & ki-ki = 200 & ki = 200 um