Question

Plesae provide a step-by-step explanation with all equations explained. This is abstract and I really want to understand it.

In a new breed of dogs, the dominant gene B determines black coat color and bb produces brown. A separate gene E, however, shows dominant epistasis over the B and b alleles, resulting in a white coat color. The recessive e allows expression of B and b. A breeder wants to know the genotypes of her three dogs, so she breeds them and makes note of the offspring of several litters. Determine the genotypes of the three dogs.

1. White female (Dog 1) X white male (Dog 2)

Offspring: 7 white, 1 black, 1 brown

2. Black female (Dog 3) X white male (Dog 2)

Offspring: 8 white, 5 black, 2 brown

Answer 1

B_ bb - Black = brown ( 1st line of . Questions E epistasis! B/b (and line) (Bled line) and E_B_} white Ebb S ee B- = Black ee bb = brown line) 3od- E-B- } white a) Ee Bb X Ee Bb '( Both het bcozygous, bg all (dowrs are present a progeny) Е. Б. / Аша ee B- Black eebb - brown ee Bb x Ee Bb E_B_ E_bb = white ee B_ - Black eebb- brown

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