Homework Answers
.Lacl produces REPRESSOR PROTIEN which binds with operator to switch -off the operon.
When lactose is given,it binds with repressor such that the operon becomes swutch-off.
Now ,when it gets mutated ,it becomes unable to bind with lactose as well as oprator site .
Hence,THE LACTOSE WILL BE SWITCH -ON ,EITHER IN THE PRESENCE OR IN ABSENCE OF LACTOSE.
.If z-gene is transcriptionally inactive ,it will never produce beta -galactosidase.
Hence lactose will never be broken through lac-opron.
Lac I ( Gene)- non functional cannot bind the inducer How does it affect in the...
Lac I ( Gene)- non functional cannot bind the inducer How does it affect in the presence of lactose? How does it affect in absence of lactose? Lac Z( protein)- Wipeout mutation How does it affect in the presence of lactose? How does it affect in absence of lactose?
Most of what we know about the lac operon in E. coli has come from the...
Most of what we know about the lac operon in E. coli has come from the genetic analysis of various mutants. Below is a list of mutants for regions of the operon. A + superscript indicates no mutation and normal function of that region, - indicates a knock out and no function of that region, c indicates the mutation resulted in constitutive action of that region. The effect of the mutation is determined by expression of the lacZ gene as...
The diagram below illustrates the LAC operon in its OFF state when the inducer molecule —lactose—is...
The diagram below illustrates the LAC operon in its OFF state when the inducer molecule —lactose—is absent. Predict the ways in which the following conditions will affect the transcription of the lactose-utilization genes. OPERON Regulatory Promoter Operator_ gene Lactose-utilization genes DNA mRNA RNA polymerase cannot attach to promoter Active repressor Protein If a mutation in the regulatory gene results in a misfolding of the repressor protein so that it can no longer bind DNA, the lactose-utilization genes O Will be...
(3 pts) There is a new mutation in the Lac/gene, called IN, that introduces a missense...
(3 pts) There is a new mutation in the Lac/gene, called IN, that introduces a missense mutation in the DNA binding domain of the protein. IN can not bind to the operator. Predict the outcome of the following lac operon genotype for the expression of functional lac enzymes in the different conditions indicated. (Note: + = wildtype, - = no functional protein made.) IN O+P+ Z-Y+ - lactose + lactose b-gal (Z) Permease (Y) b-gal (Z) Permease (Y) + +...
B2. Consider E. coli cells, each having one of the following mutations: a) a mutant lac...
B2. Consider E. coli cells, each having one of the following mutations: a) a mutant lac operator (Oc locus) that cannot bind repressor. b) a mutant lac repressor (I- gene product) that cannot bind to the lac operator. c) a mutant lac repressor (the Is gene product) that cannot bind to lactose. d) a mutant lac promoter that cannot bind CAP + cAMP. What effect would each mutation have on the function of lac operon (assuming no glucose is present)...
Imagine you are carrying out research on the lac operon. You isolate six mutations in the...
Imagine you are carrying out research on the lac
operon. You isolate six mutations in the lac operon by
measuring the amount of beta-galactosidase made in mutant cell line
under three different conditions: no lactose/no glucose; lactose
only; and lactose/glucose. Your results are shown in the table.
Strain
No Lactose, No Glucose
Lactose
Lactose, Glucose
Wild-type
None
High
Low
Mutant 1
None
None
None
Mutant 2
None
None
None
Mutant 3
None
Low
Low
Mutant 4
None
Low
Low
Mutant...
A. Describe in detail the regulation of the prokaryotic lac operon for the following environment: Glucose...
A. Describe in detail the regulation of the prokaryotic lac operon for the following environment: Glucose is present, lactose present, & the repressor protein is mutated such that the allosteric site is non-functional and can no longer bind its substrate. Be sure to specify the presence or absence and location of Lac I, allolactose, cAMP, CAP, and RNA polymerase. B. Indicate whether transcription is occurring at a basal level, a high level, or not at all.
4. Nutritional status, mutation, and expression of the lac operon. For each of the following conditions,...
4. Nutritional status, mutation, and expression of the lac operon. For each of the following conditions, indicate how much (a lot, a little, or none) of the lacZ gene (z-gene) product, beta- galactosidase, is being synthesized. NUTRITIONAL STATUS OF THE BACTERIA +lactose/-glucose +lactose/+glucose -lactose/+glucose genetic status normal (no mutation) mutation a mutation b mutationc important: these are nor the same mutations as the ones in your class handout mutation a: a mutation in the start codon for the lacA (A-gene)...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial strains. Bacterial strains that are "partially diploid" have two copies of the lac operon because they aquired a plasmid carrying just the lac operon region. One copy of the lac operon region is on the recipient's bacterial chromosome, and the other copy is on the F' plasmid that was introduced into the cell by conjugation. Partial diploid genotypes are written with the F' segment...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial strains. Bacterial strains that are "partially diploid" have two copies of the lac operon because they aquired a plasmid carrying just the lac operon region. One copy of the lac operon region is on the recipient's bacterial chromosome, and the other copy is on the P plasmid that was introduced into the cell by conjugation. Partial diploid genotypes are written with the P segment...
The diagram below illustrates the LAC operon in its OFF state when the inducer molecule —lactose—is absent. Predict the ways in which the following conditions will affect the transcription of the lactose-utilization genes. OPERON Regulatory Promoter Operator_ gene Lactose-utilization genes DNA mRNA RNA polymerase cannot attach to promoter Active repressor Protein If a mutation in the regulatory gene results in a misfolding of the repressor protein so that it can no longer bind DNA, the lactose-utilization genes O Will be...
(3 pts) There is a new mutation in the Lac/gene, called IN, that introduces a missense mutation in the DNA binding domain of the protein. IN can not bind to the operator. Predict the outcome of the following lac operon genotype for the expression of functional lac enzymes in the different conditions indicated. (Note: + = wildtype, - = no functional protein made.) IN O+P+ Z-Y+ - lactose + lactose b-gal (Z) Permease (Y) b-gal (Z) Permease (Y) + +...
Imagine you are carrying out research on the lac
operon. You isolate six mutations in the lac operon by
measuring the amount of beta-galactosidase made in mutant cell line
under three different conditions: no lactose/no glucose; lactose
only; and lactose/glucose. Your results are shown in the table.
Strain
No Lactose, No Glucose
Lactose
Lactose, Glucose
Wild-type
None
High
Low
Mutant 1
None
None
None
Mutant 2
None
None
None
Mutant 3
None
Low
Low
Mutant 4
None
Low
Low
Mutant...
4. Nutritional status, mutation, and expression of the lac operon. For each of the following conditions, indicate how much (a lot, a little, or none) of the lacZ gene (z-gene) product, beta- galactosidase, is being synthesized. NUTRITIONAL STATUS OF THE BACTERIA +lactose/-glucose +lactose/+glucose -lactose/+glucose genetic status normal (no mutation) mutation a mutation b mutationc important: these are nor the same mutations as the ones in your class handout mutation a: a mutation in the start codon for the lacA (A-gene)...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial strains. Bacterial strains that are "partially diploid" have two copies of the lac operon because they aquired a plasmid carrying just the lac operon region. One copy of the lac operon region is on the recipient's bacterial chromosome, and the other copy is on the P plasmid that was introduced into the cell by conjugation. Partial diploid genotypes are written with the P segment...
Most questions answered within 3 hours.
-
Twenty replicates of a single bottle of quality control material
were analyze for hemoglobin. The mean...
asked 26 minutes ago -
1-For this Pause-Problem, pick two other levels of NOIR (other
than Interval, that is) and write...
asked 15 minutes ago -
If you want to invest into a stock A for one year, and given
that during...
asked 22 minutes ago -
C programming help!
Write a program that reads the electricity consumption (in kWh)
and computes the...
asked 8 minutes ago -
General Corporation has $900,000 of service revenue, a $15,000
captial loss, a $20,000 casualty loss, operating...
asked 16 minutes ago -
When comparing a highly liquid bond with a comparable
but less liquid bond, the highly liquid...
asked 21 minutes ago -
(a)
Consider the market for used cars as presented in class and in
the course notes.Let...
asked 26 minutes ago -
consider the inelastic collision of two balls on the
same line. we take the direction to...
asked 30 minutes ago -
1. Drying of sample in Diels Alder Reaction lab experiment
a) Why must a sample be...
asked 28 minutes ago -
a 90Kg skier glides down a slope with an incline of 17 degrees,
what frictional force...
asked 39 minutes ago -
1. Weights of
Pikachu’s in the wild are normally distributed with a mean of 13.2
lbs...
asked 45 minutes ago -
Using the table of standard reduction potentials, answer True or
False.
The reaction:
2Cu(s) + 2H+(aq)...
asked 47 minutes ago