Question

In bluebirds, there is an autosomal gene called the feather gene. This gene codes for the feather protein, and this protein controls the color of the feathers. A base- substitution mutation in the feather gene results in a bird with black feathers. When this black-feathered bird mates with a true-breeding normal blue-feathered bird (a black x normal cross), the F1 offspring all have normal blue feathers. Next to each statement below, indicate True or False. The black feather gene allele is recessive. [Select ] Select The mutation must have resulted in a frameshift in the feather gene. (Select The mutation is most likely a silent mutation. (Select] The true-breeding normal blue-feathered bird is homozygous for the feather gene, Select All of the F1 offspring are heterozygous for the feather gene. [ Select If you mate the F1 offspring together (cross F1x F1), 75% of the birds in the next generation (the F2 generation) will have normal blue feathers and 25% of the birds vill have black feathers. [Select]

Answer 1

o Yes, the black feather gene allele is - recessive, because when black feathered bird i i mated with blue, all the Fq progeny are blue. So it means the black feather allele is not able to express eis heterozygous condition No, it does not result is a Xowe skype, be coшe Рамаар 60 I occurs due to addition or deletion I & not substitution mutation 19 No, the mutation is not silent mutation because its effect is clearly Visible. Silent mutations are those in which the changed codon codes for same amino acid so that Pheno- type remains same a bird is ② Yes, tame breeding blue bird is homozygous. The breeding itself means being homozygous, E o yes, all for individuals are heteros- ygorys - ® Yes, in fz 75% individuals will be - blue 8.25% black because it shones a dominant - recessive relationship with 311 ratio