Wild type 710 green 70 dwarf 140 dwarf, curly leaves 90 green, dwarf, curly leaves 680...
Wild type 710
green 70
dwarf 140
dwarf, curly leaves 90
green, dwarf, curly leaves 680
green, curly leaves 150
Determine order and distance between genes
Homework Answers
Answer:
Wild type 710 (+ + +)
green 70 (g + +)
dwarf 140 (+ d +)
dwarf, curly leaves 90 (+ d c)
green, dwarf, curly leaves 680 (g d c)
green, curly leaves 150 (g + c)
Total = 1840
Hint: always parental combinations are more numbered than any other recombinants in linkage. Hence, parental trihybrid would be +++/gdc.
1). If single cross over occurs between g&d...
Normal : ++/gd
After cross over: + d/g +
+ d progeny= 140+90=230
g + progeny= 150+70=220
Total of this progeny= 450
Recombination frequency between g & d = (no. of recombinants/total)100
= (450/1840)100= 24.46%
2). If single cross over occurs between d and c...
Normal: ++/dc
After cross over: +c/d+
+c progeny= 150
d + progeny= 140
Total of this progeny= 290
Recombination frequency between d&c= (290/1840)100
= 15.76%
3). If single cross over occurs between g and c...
Normal: ++/gc
After cross over: +c/g+
+c progeny= 90
g + progeny= 70
Total of this progeny= 160
Recombination frequency between g&c= (160/1840)100= 8.7%
Recombination frequency (%) = Distance between genes (m.u.)
Order of genes = g------8.7m.u.-----c----15.76m.u.-------d
Gene order= g----c---d
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