The mean yield of a particular variety of grain crop is 200 bu/acre (bushels per acre). If the top yielding 20% of the plants are selected for breeding and mated randomly among themselves, this is equivalent to a selection differential S of S = 37 bu/acre. What is the expected mean yield of the progeny of the selected parents if the heritability of yield is 0.428? (hint: don’t forget that the response (R) to selection represents the new value of a trait in the offspring generation, not the change in that value).
We have,
Selection Differential = 37 bu/acre
Selection Response
= Average yield of Progeny - Average yield of parental crop
= A - 200 bu/acre
h2 = 0.428
From the Breeder's Equation:
h2 = R/S
=> 0.428 = (A - 200)/37
=> A = (0.428 * 37) + 200 = 215.836
The means that the Mean Yield of the Progeny population is 215.836 bushels/acre
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