Question

n Thick hair a as that there w er the following hird Dark CA) is dominant over Light e rendentementene pairs A cow breeder TAA TA - (FTF F2 maring gave the following results: 661 Thick hair, Dark horn 225 Thick hair, Light horn 221 Fine hair, Dark horn 77 Fine hair, Light horn Total 1184 Assume normal Mendelian genetics, Dihybrid F2 cross and answer O 1-8 1. What is the expected ratio 2. What are the expected results 3. For these results, state the null hypothesis 4. What is the Alternative Hypothesis for these results How many degree of freedom this mating have What probability does your X- correspond to this value significant or not significant (according to the x table) ich hypothesis is supported by the results of your x test stock solution, you need to do 1:10,000 dilution in a final volume of 10 ml. wo ways of obtaining the dilution and explain which way is best (most accurate).

I don't understand 5-9

Answer 1

5. Degree of freedom = no. of observed phenotypes - 1 = 4 - 1 = 3.

6.

6. Observed Enfreeted oE (0-E" Cort 661 666 -5 225 0.037 225 222 + 3 9 0.040 221 222 -1 0.004 77 74 13 9 00121 50.202 . p-value for 2 = 0.202 at df = 3 is = 0.97

7. According to chi square table, this value is not significant at critical value of 0.05.

8. As the P value of this chi square test for the difference between observed value and expected value is not significant, Null hypothesis is supported by the chi square test.

I'm unable to answer #9 as it's not visible completely. Kindly post that question separately. Thanks and Regards.