Question

n Thick hair a as that there w er the following hird Dark CA) is dominant over Light e rendentementene pairs A cow breeder TAA TA - (FTF F2 maring gave the following results: 661 Thick hair, Dark horn 225 Thick hair, Light horn 221 Fine hair, Dark horn 77 Fine hair, Light horn Total 1184 Assume normal Mendelian genetics, Dihybrid F2 cross and answer O 1-8 1. What is the expected ratio 2. What are the expected results 3. For these results, state the null hypothesis 4. What is the Alternative Hypothesis for these results How many degree of freedom this mating have What probability does your X- correspond to this value significant or not significant (according to the x table) ich hypothesis is supported by the results of your x test stock solution, you need to do 1:10,000 dilution in a final volume of 10 ml. wo ways of obtaining the dilution and explain which way is best (most accurate).

don't understand

1-4

Answer 1

1. If Mendelian genetics is applied, then the expected ratio in F2 dihybrid cross is

9 (thick hair, dark horn) : 3 (thick hair, light horn) : 3 (fine hair, dark horn) : 1 (fine hair, light horn).

2. Expected results can be calculated by multiplying the total number of offsprings by the ratio of each phenotype.

Thick hair, Dark horn = (9/16) × 1184 = 666

Thick hair, Light horn = (3/16) × 1184 = 222

Fine hair, Dark horn = (3/16) × 1184 = 222

Fine hair, Light horn = (1/16) × 1184 = 74

3. Null hypothesis: The genes for hair and horn segregate equally and assort independently during gamete formation.

4. Alternative hypothesis: The genes for hair and horn don't assort independently and are linked.

Explanation- Null hypothesis suggests that there is no significant difference between the observed values and the expected values; and any difference that may exist is due to a matter of chance.

Alternative hypothesis suggests that there is a significant difference between the observed values and expected values; and the null hypothesis should not be considered true for that result.

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