Question

There are four possible outcomes for a gene combination of Aa x Aa. Use a piece of scratch paper to complete to Punnett squar
A green pea plant (Gg) is crossed with a yellow pea plant (gs). What are the chances that they will produce a yellow pea plan
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Answer #1

1.

A a
A AA Aa
a Aa aa

AA is homozygous dominant and 1 out of 4 offspring pair is AA and the answer is

1 out of four (1:4) or 25 %

2.

G g
G GG gg
g Gg gg

Genotype of yellow pea plant is gg and 2 out of 4 progeny has gg genotype

Hence the answer is 2 out of 4 (2:4) or 50 %

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