Question

If the difference in pH between the mitochondrial matrix and inter-membrane space is approximately 0.75 pH units, how much energy is stored in the gradient per mole of H* transferred (pumped)? Assume a temperature of 37°C and a trans (inner) membrane potential of 0.20 V. ach

answer is 24 kj/mol

can someone explain the answer?

Answer 1

Ans. ∆p = ∆$\psi$ - (0.059V)∆pH

Here, ∆p denotes the proton motive force

∆$\psi$ denotes difference in charge across membrane in volts

∆pH denotes the difference in pH

∆p = 0.20 - (0.059)*0.75

= 0.15575V