In the liver mitochondria, the membrane potential is -0.17 V (negative inside). The pH difference is -0.5 (pHoutside – pHinside). The charge on a proton is (+1). What is the proton motive force (the amount of energy stored in the gradient)?
The Gibbs free energy for the gradient is [96485 X -.17] + [2.303 X 8. 315 X 310 X -0.5] = -19.4 kJ/mol.
Please explain the formula and what is the question asking for, Thank you.
The question is asking for proton motive force
∆G = nF∆psi - 2.303nRT ∆pH
∆ psi = membrane potential = -0.17 , n = 1
F = 96485 , R = 8.313 (gas constant) , T (temp in kelvi ) = 310K
Here we have to calculate the amount of energy stored in the gradient
So , ∆G = (96458 × - .17) + ( 2.303 × 8.315 × 310 × -0.5)
= -19.36 KJ/mol.
In the liver mitochondria, the membrane potential is -0.17 V (negative inside). The pH difference is...
What is the pH difference (△pH) across a membrane at 310 K if the membrane potential is -0.15 V and the overall Gibb's free energy change across the membrane is -19 .0 kJ mol-1? (R = 8.315 J/mol-K; F = 96,485 J/V-mol). Please show me all the steps of how to solve this. Thank you!
answer is 24 kj/mol
can someone explain the answer?
If the difference in pH between the mitochondrial matrix and inter-membrane space is approximately 0.75 pH units, how much energy is stored in the gradient per mole of H* transferred (pumped)? Assume a temperature of 37°C and a trans (inner) membrane potential of 0.20 V. ach
NUMBER 10 PLEASE
-Kor Cor The Henry's law constant of oxygen in water at 25 °C is 773 atm mol'' kg of water. Calculate the molality of oxygen in water under a partial pressure of 0.20 atm. Assume that the solubility of oxygen in blood at 37 °C is roughly the same as that in water at 25 °C, comment on the prospect for our survival without hemoglobin molecules. The total volume of blood in the human body is about...