Question

QuesLIUI IU A special strain of wild type yeast can produce both an "Important Biomolecule" and a "Super Stinky Biomolecule" in the pathway shown below. You have two haploid mutants (Mut1 and Mut2). Mut1 produces the "important biomolecule" at low levels and is mildly stinky. Mut2 is still super stinky but cannot produce the "important biomolecule". Which of the options below are consistent with the experimental observations? Compound E (odorless) Important Biomolecule (odorless) ... eru2 - Compound A (odorless) Compound B- (odorless) Compound (odorless) Super Stinky Biomolecule Mut 1 is a mutant of enz2 or enz3 Mut 2 is a mutant of enz5 Mut 2 is a mutant of enz3 Mut 1 is a mutant of enz4 A and B are consistent with the phenotype

Answer 1

Since the Mut 1 is able to make both stinky biomolecule and important biomolecule the enzyme 4 and 5 are normal. But the production rate is low means the flux of substrate is not sufficient to meet the demand of enzyme 4 and 5 proving that Mut 1 has mutation in either enzyme 2 or 3 due which these enzyme are not very efficient to convert substrate into product with a considerable rate.

Mut 2 is not able to make super stinky biomolecule at all means the enzyme 5 is mutated.

So option 1 and 2 are correct.