Question

In a cross between individuals with the following genotypes for 5 hypothetical genes: AaBbCCDdee x aaBBccDdEe; what is the probability that that one of the progeny would have a dominant phenotype (assume classical dominant/recessive pattern of inheritance for all 5 genes.?

		1/16
		3/16
		1/32
		3/32

Answer 1

AaBbCCDdee x aaBBccDdEe

Now we will calculate the probability of getting dominant phenotype for each gene,

for A gene,

	A	a
a	Aa	aa
a	Aa	aa

So, the probability = 1/2.

for B gene,

	B	b
B	BB	Bb
B	BB	Bb

So, the probability = 1.

for C gene,

	C	C
c	Cc	Cc
c	Cc	Cc

So, the probability = 1.

for gene D,

	D	d
D	DD	Dd
d	Dd	dd

So, the probability = 3/4.

for gene E,

	e	e
E	Ee	Ee
e	ee	ee

So, the probability = 1/2.

So, the probability that that one of the progeny would have a dominant phenotype = 1/2 * 1 * 1 * 3/4 * 1/2 = 3/16.