The data below is from a series of two-point crosses.
pr – adp 21%
pr – vg 29%
vg – adp 8%
Answer:
a). Recombination frequency (%) = Distance between genes (mu)
Genetic map: pr------21mu------adp----8mu-----vg
b).
After inserting cv in the genetic map, now see below genetic map of all 4 genes.
pr--4--cv----17--adp-8—vg
Now the distance between cv and adp is 17 mu and ther outcome of the cross between cv and adp is 17%.
The data below is from a series of two-point crosses. Use the recombination frequencies to construct...
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genetics-please show all work
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