Question

WILL SOMEONE PLEASE EXPLAIN THIS TO ME? I WILL LEAVE RATING AND COMMENT, THANK YOU :)

1. For each test tube in the Avery, Macleod, and McCarty experiment, circle the macromolecules from the Type IIIS strain filtrate that you would expect to be found in the test tube after the treatment. Circle ‘None” if none of the macromolecules are present.

Tube A. No filtrate RNA DNA    Protein None

Tube B. No enzyme RNA DNA Protein None

Tube C. RNase RNA DNA Protein None

Tube D. Protease RNA DNA Protein None

Tube E. DNase RNA DNA Protein None

2. If the contents of each tube were injected into the mouse, which would kill the mouse and why?

This was based off a genetics virulent experiment done by Drs. Avery, Macleod and McCarty.

Answer 1

Answer(1): Avery, Macleod, and McCarty experiment was based on transformation. Cell free extract of SIII starin bacterium was subjected to DNase, RNase and Protease. Each treated extract was mixed with RII and mixture injected to mouse to see transformation. In case of Protease and RNase transformation was recorded. In case of DNase no transformation was recorded. Their experiment revealed that the chemical nature of the transforming substance to be DNA. With the help of experiment they showed that DNA isolated from SIII strain bacteria could confer the pathogenic properties to RII strain bacteria.

Two conclutions were derived:

1. Active factor is DNA which can cause transformation
2. SIII strain contains the Active factor

So according to me "Tube E. DNase RNA DNA Protein None" should be correct answer of your question.

Answer(2): If the contents of each tube were injected into the mouse, then mouse did not survive when injected with a mixture of live, avirulent (smooth) Streptococcus pneumoniae and heat‑killed, virulent Streptococcus pneumoniae.