Question

Mendelian Genetics Lab Practice Mendelian Genetics Lab Practice Practice with Crosses. Show all work below: 9. In pea plants purple flowers are dominant to white flowers. Two white flowered plants are crossed... 5. ATT (tall) plant is crossed with a short plant). What percentage of their offspring wil have white flowers? What percentage of the offspring will be tall? 10. A white flowered plant is crossed with a plant that is heterozygous for the trait. 6. Show the cross of a Ty plant and a Ti plant What percentage of the offspring will have purple flowers? What percentage of the offspring will be short? What percentage is tal? 11. Two plants, both heterozygous for the gene that controls flower color are crossed. What percentage of their offspring will have purple flowers? 7. A heterozygous round seeded plant (Rnis crossed with a homozygous round seeded plant (RRI What percentage will have white flowers? What percentage of the offspring will be homozygous (RRY? 12. In guinea pigs, the allele for short hair le dominant What genotype would a heterozygous short haired guinea pig have? 8. A homozygous round seeded plant is crossed with a homozygous wrinkled seeded plant. What genotype would a pure breeding short haired guinea pig have? What are the genotypes of the parents? What genotype would a long-haired guinea pig have? What percentage of the offspring will also be homozygous? Show the cross for two heterozygous guinea pigs. What is the genotype of all of the offspring? What percentage of the offspring will have short hair? What percentage of the offspring will have long hair?

Answer 1

Ans - attaching image .

Parent x tt tt (2) TITETE TTE TE - 100% offsprings are tall as all contain one T do allele which is dominant. (6 Parent - Tt X TE To T t (4) TITT TET ETE Itt 25% offsprings will be shoot 75% offsprings will be tall, that is ( 25% - Tt, homozygous tall 2 50.). - Tt heterozygous tally

et, @ altele allele for purple flower = k ) for white flower w so po ww. x ww W WW WW WW [ 9 ) มย ผม w ww ww 100% offsprings have white flowers. la ww X Ww (2) W w Ww wwwww WW Σ ets 0 50 percentage offsprings have people formes - ww & Ww. Wwwww WW wwwww 75.1. Offsprügs will have purple flowers (ww, ww) 257. i 1 u white l .(ww).

A - Rr x RR. R 19) RR RVT R RR RV I ñ and 50% beeds are homosygons dominant (round). 50% seeds are beterozygous dot round is hou & - RR & wr. homozygous round genotype – RR homozygoue rorinkled genotype-rr. rv 19 gen novinkled - rr. homozygous R RV I Rr US 10% percentage of the offsprings are homosygous geratype of all offeprings – Rr (heterozygous round) co

Wb e (12 let, allele for till hair be s (recessive) I allele for short hair be ß (dominant) genotype- referozygous short haired - Se. - Pure breeding short hair = 68 - long haired guinea pig = ss. cross two heterocy goes guinea pige P- Sex Sense & (osss San 757. offsprings will have short hair (48, S& genotype) 257. – offspringe will have long hair (35)

Exopanation ,take an example of round seeds

R represents round ( dominant)

and ,r = wrinkled .( Recessive)

So homozygous means both alleles are similar eg- RR and rr.

Heterozygous means both are different for the same trait that is Rr.

Now for a plant to be round in the gene atleast one allele shpuld be dominant that is R .

So homozygous RR will appear round and Rr ( heterozygous) will also appear round . As one allele R is dominant.

Now for recessive trait to be expresed , the genotype must be homozygous that is rr.

Genotype refers to the genetic constitution. That is the gene pair . Whethet its homoxygous round RR ,or heterozygoud round Rr, or homozygous wrinlked rr.

Now phenotype is the trait which is physically expressed or visible to the eye so the plant seed will be Round in two cases RR genotype and Rr genotype .

The plant seed phenotype is wrinlked only in one case that is rr genotype as recessive alleles need to be in a pairto be expressed .

If this helps give it a positive rating ,thank you!