Question

Assignment Chapter X Chapter pdf + @ fit to page 1 Pageview | A Solve the follow the answer should be greater than one pere) Is a certain poce o fdebypfows through the incippe is the figure AU tube with the pressure defence betwee points 1 and 2 shows The L The flow is the faithe www Fidepressions of pares Discuss the code for there to be With the pipe 3 w w w .from 1 to 2? 4 With flow down from 2019 For , 45, 90 degree s the conditionen any for there to be 5 w tow the pipe with flow from 1 29 with two from 2 to 11 crosoft Edge - the fast now bromer built for Windows 10,

Answer 1

Solution : t sin o ŹB According to hy drostatic law, · P + fjs +sgh -- Smghfgs, pg(1:16) P= = fg ising + ogls + Samgh-sgh- = $3.1 side + imgh-sgh nB = fglume + gh ($m-) Expression zol pre = fgLsine + (Sm+3) gh - Nete scaly conditions parih Hled Energy at O'qi= + + 37 Head Energy at ce by tengti, (4-3) = + VERWE +(513) síce pipe is of unizem. (20ss section, v=V (-6) = m + (33) 12

(99) – + (-time) (3-3 = -1sije) - I sino (53Lsíne +(3m 598h) - Istine - 1 cha + Sm 3 h – usne No How in pipe & enero (m 2 ) ho since : stim; ® Flow glom 1 to 2 9- 30 → Son 5)hso . » (Im-9) ho (Sm-7) >0 & hzo (81) Im I to thao Th>o ... since Imps qol : U-tube menomet, This is the case shown in the given zigure

© glow grom @ to . (9-3) <0 → Smi-)h <0. (Im 9) >0 tho (1) Gm 5) 0 4 ho possible. Theol Impossible EN 6 6 20 : The value of h doesn't depend on the angle of malination 8: pipe since #tal enegy head dizzolence epe = (fm 3 ) h doesn't depend me. n